I need to find the value of y in this right trapezoid. First, I should recall that a right trapezoid has two right angles, but I'm not sure if that's directly helpful here. Looking at the diagram, there's a 120-degree angle marked, and two angles labeled with expressions in x and y, and some parallel sides indicated by the arrows.

The problem mentions it's a right trapezoid, so probably the 120-degree angle is one of the right angles? But 120 degrees isn't a right angle; right angles are 90 degrees. That might be a mistake in my assumption.

Perhaps the 120-degree angle is not a right angle, but the trapezoid has right angles elsewhere. The arrows indicate parallel sides, so that's key. In a trapezoid, there's one pair of parallel sides.

Looking at the diagram, the two sides with pink arrows are parallel. So, let's denote the trapezoid as ABCD, where AB and CD are the parallel sides, with AB being the top base and CD the bottom base.

The angle marked 120 degrees is at vertex A, I think. Then, at vertex B, there's an angle labeled (3y + 40) degrees. At vertex D, there's an angle labeled x degrees, and at vertex C, there's an angle labeled (3x - 70) degrees.

The side with the arrow going out is probably the extension, but I think the angle (3x - 70) is an exterior angle or something? The arrow is pointing away, so likely (3x - 70) is an exterior angle.

The diagram shows an angle outside the trapezoid at the top right, labeled (3x - 70) degrees. Similarly, the angle at the bottom left is 120 degrees, which is inside.

Since AB and CD are parallel, I can use properties of parallel lines and transversals.

Let me sketch this mentally. Assume AB is the top base, CD the bottom base, with AB parallel to CD.

Angle at A is 120 degrees. Then, moving clockwise, at B, there's an angle (3y + 40) degrees. Then at C, there's an exterior angle (3x - 70) degrees, and at D, x degrees.

The exterior angle is given, so probably the interior angle at C is supplementary to that.

In a polygon, an exterior angle is supplementary to the adjacent interior angle.

So, if the exterior angle at C is (3x - 70) degrees, then the interior angle at C is 180 - (3x - 70) = 180 - 3x + 70 = 250 - 3x degrees.

Similarly, at other vertices, we have interior angles.

Now, for a trapezoid with parallel sides AB and CD, the consecutive angles between the parallel sides are supplementary. That is, angle A + angle D = 180 degrees, and angle B + angle C = 180 degrees, because they are same-side interior angles.

Is that correct? Let me confirm.

If AB || CD, and AD is a transversal, then angle A and angle D are same-side interior angles, so they sum to 180 degrees.

Similarly, if BC is a transversal, angle B and angle C sum to 180 degrees.

Yes, that's right.

So, in this trapezoid:

Angle at A is 120 degrees.

Angle at D is x degrees.

Since AB || CD, angle A + angle D = 180.

So, 120 + x = 180.

Therefore, x = 180 - 120 = 60 degrees.

Is that it? But I have other angles.

Angle at B is (3y + 40) degrees.

Angle at C is the interior angle, which we said is 250 - 3x degrees.

And since angle B + angle C = 180, because AB || CD.

So, let's use that.

First, from angle A and angle D: 120 + x = 180, so x = 60.

Now, interior angle at C is 180 - exterior angle = 180 - (3x - 70) = 180 - 3x + 70 = 250 - 3x.

Plug in x=60: 250 - 3*60 = 250 - 180 = 70 degrees.

Now, angle B + angle C = 180.

Angle B is (3y + 40).

Angle C is 70 degrees.

So, (3y + 40) + 70 = 180.

Simplify: 3y + 110 = 180.

Then, 3y = 180 - 110 = 70.

So, y = 70 / 3 ≈ 23.333, but that's not an integer, and the choices are 10,20,30,70, all integers. 70/3 is about 23.33, not matching.

I must have made a mistake.

Perhaps the 120 degrees is not angle A, or I misidentified the angles.

Maybe the trapezoid is oriented differently.

Another thought: the 120 degrees might be an exterior angle or something, but the diagram shows it inside.

Looking back at the diagram: it shows a quadrilateral, with angles labeled. Bottom left is 120 degrees, top right has an exterior angle labeled (3x-70), and inside at top left is (3y+40), and at bottom right is x degrees.

The arrows are on the two non-parallel sides? No, the arrows are on the sides that are probably the legs.

The problem says "right trapezoid", which typically means it has two right angles.

In this case, angle at A is 120, which is not right, so probably the right angles are elsewhere.

Perhaps angle at D and angle at B are right angles, but angle at D is x, which we found 60, not 90.

I need to use the fact that it's a right trapezoid.

Maybe only one right angle, but usually it has two adjacent right angles.

Assume that angle at D is 90 degrees, but we have x=60 from earlier, which is not 90.

Perhaps I miscalculated x.

From angle A + angle D = 180, with angle A=120, so angle D=60, that seems correct for parallel sides.

But then angle C is 70, angle B is 110 if it were, but 3y+40 +70=180, so 3y+40=110, 3y=70, y=70/3 not integer.

But choices are integers, so probably wrong.

Perhaps the parallel sides are not AB and CD as I thought.

The arrows: there are two arrows, one on the left side and one on the right side. The left arrow is horizontal, and the right arrow is slanted, but both have arrows indicating direction, but for parallel, the arrows should be parallel if the sides are parallel.

In the diagram, the two sides with arrows are parallel, I think. The arrow on the left is horizontal, and on the right is at an angle, but if they are parallel, they should have the same slope.

Perhaps in the diagram, the two legs are not parallel, but the bases are.

I think I need to interpret the diagram correctly.

From the description: "the right trapezoid" with angles: bottom left 120 degrees, top left (3y+40), bottom right x, and top right exterior (3x-70).

And the sides: the left side is from bottom left to top left, with 120 at bottom, (3y+40) at top.

The bottom side is from bottom left to bottom right, with 120 at bottom left, x at bottom right.

The right side is from bottom right to top right, with x at bottom, and at top, there's an exterior angle (3x-70), so the interior angle at top right is supplementary, 180 - (3x-70) = 250 - 3x, as I had.

The top side is from top left to top right, with (3y+40) at top left, and the exterior angle at top right.

Now, for it to be a trapezoid, one pair of sides is parallel.

Given that it's a right trapezoid, likely it has two right angles. The 120 degree angle is obtuse, so probably not a right angle. So the right angles are probably at the bottom right or top left.

But angle at bottom right is x, which we thought was 60, not 90.

Perhaps the parallel sides are the top and bottom, which are horizontal in the diagram, I assume.

In that case, with AB || CD, then angle at A and angle at D should be supplementary, which is 120 + x = 180, x=60.

Similarly, angle at B and angle at C supplementary.

Angle at B is (3y+40), angle at C is 250 - 3x = 250 - 180 = 70, as before.

Then (3y+40) + 70 = 180, so 3y+110=180, 3y=70, y=70/3 not integer.

But choices are 10,20,30,70, so 70 is there, but 70/3 is not 70.

y=70/3 ≈23.33, not in choices.

Perhaps the exterior angle is not at C, but the label is outside.

Another idea: perhaps the angle (3x-70) is not an exterior angle, but an interior angle. But the arrow is pointing out, so likely it's exterior.

Maybe for the trapezoid, the parallel sides are the left and right, but that would make it a rectangle if both pairs parallel, but it's a trapezoid, so only one pair parallel.

If left and right are parallel, then it would be a trapezoid with parallel sides vertical.

In that case, the bottom and top would not be parallel.

Let me try that.

Suppose that the two legs are parallel. That is, the left side and the right side are parallel.

Then, the bases are the top and bottom.

In a trapezoid with parallel legs, it's possible, but usually trapezoids have parallel bases.

But mathematically, it's possible.

So, assume that AD and BC are parallel, where A is bottom left, D is bottom right, B is top left, C is top right.

In standard notation, let's say A bottom left, B top left, C top right, D bottom right.

So, if AD and BC are parallel, but AD is bottom, BC is top, so if AD || BC, then both pairs are parallel, which makes it a parallelogram, but a trapezoid has exactly one pair parallel, so that can't be.

AD is from A to D, which is bottom, BC is from B to C, top. If AD || BC, and AB and CD are the legs, but if AD || BC, and it's a quadrilateral, then it must be a parallelogram, so both pairs opposite sides parallel, but trapezoid requires exactly one pair, so this is not possible.

Therefore, the parallel sides must be the top and bottom, AB and CD, with AB || CD.

So my initial assumption should be correct.

But then why is y not integer?

Perhaps the 120 degrees is not the interior angle, but something else.

Or perhaps it's an exterior angle.

The diagram shows "120°" at the bottom left, and it's inside the shape, so it should be interior angle.

Another thought: in a right trapezoid, there are two right angles. So likely, at D and at B or something.

From the diagram, at bottom right, angle is x, at top left is (3y+40), and we have 120 at bottom left.

If it's a right trapezoid, perhaps angle at D is 90 degrees, so x=90.

Then, if AB || CD, angle A + angle D = 180, so 120 + 90 = 210 ≠ 180, contradiction.

So not both.

Perhaps angle at A is 90, but it's 120, not 90.

So the right angles must be at B and D or something.

Assume that angle at D is 90 degrees, so x=90.

Then, if AB || CD, angle A + angle D = 180, 120 + 90 = 210 ≠ 180, impossible.

Similarly, if angle at B is 90, so 3y+40 = 90, then 3y=50, y=50/3 not integer.

Or angle at C is 90.

Interior angle at C is 250 - 3x, set to 90, so 250 - 3x = 90, 3x=160, x=160/3 not integer.

Not working.

Perhaps the parallel sides are not AB and CD.

Another idea: perhaps the two sides with arrows are the parallel sides, and the arrows indicate they are parallel.

In the diagram, there is an arrow on the left side and on the right side. The left arrow is on the leg from A to B, and the right arrow is on the leg from D to C.

But if both legs have arrows, and they are parallel, then the trapezoid has parallel legs, which would make it a parallelogram, but again, trapezoid requires exactly one pair parallel, so if legs are parallel, then both pairs are parallel, contradiction.

Unless the arrows are on the bases, not the legs.

Let's read the diagram carefully.

The user said: "the arrow moves around the figure" but that was in previous problem. For this diagram, it's a static diagram.

From the image link, but I have to interpret from the description.

In the text, it's described as "the right trapezoid" with angles labeled, and choices for y.

Perhaps "right trapezoid" means it has a right angle, and we need to find which one.

But we have a 120 degree angle, so not all right.

Another thought: perhaps the 120 degrees is the angle between the bases, but no, it's at the vertex.

Let's look at the exterior angle.

The exterior angle at C is (3x-70), so for the transversal.

Since AB || CD, and BC is a transversal, then the consecutive interior angles sum to 180.

But angle at B and angle at C are on the same side of the transversal BC.

Transversal is BC, parallel lines AB and CD.

Then, angle at B, which is angle ABC, and angle at C, angle BCD, are same-side interior angles, so they sum to 180 degrees.

Yes, as I had earlier.

Similarly for the other side.

But we got y=70/3 not integer.

Perhaps the angle (3y+40) is not at B, but at another vertex.

Or perhaps it's the angle at the top, but for the trapezoid.

Another idea: in the diagram, the 120 degrees might be the angle of the trapezoid at A, but when they say "right trapezoid", it might mean that one of the angles is right, and we need to find it.

But with the given, it's not working.

Perhaps I miscalculated the interior angle at C.

The exterior angle is (3x-70), and it's adjacent to the interior angle at C, so interior + exterior = 180, so interior = 180 - (3x-70) = 250 - 3x, as before.

Then with x=60, interior at C is 70.

Then angle B + angle C = 180, so angle B = 110.

But angle B is (3y+40), so 3y+40 = 110, 3y=70, y=70/3.

But 70/3 is not in choices, and choices include 70, so perhaps y=70, but 3*70+40=210+40=250, which is not 110.

No.

Perhaps the expression (3y+40) is for a different angle.

Let's read the diagram again.

"Find the value of the variable y in the right trapezoid."

Angles: bottom left: 120°, top left: (3y+40)°, bottom right: x°, top right: exterior (3x-70)°.

And it's a right trapezoid, so likely it has a right angle at one corner.

Suppose that at bottom right, angle is 90 degrees, so x=90.

Then, if AB || CD, angle A + angle D = 180, 120 + 90 = 210 ≠ 180, impossible.

If at top left, (3y+40) = 90, then 3y+40=90, 3y=50, y=50/3 not integer.

If at top right, interior angle is 90, so 250 - 3x = 90, then 3x=160, x=160/3 not integer.

So no right angle at the vertices? But that can't be for a right trapezoid.

Perhaps "right trapezoid" means something else, but I think it means it has a right angle.

Another possibility: the 120 degrees is not the interior angle, but the angle of the extension or something, but the diagram shows it at the vertex inside.

Perhaps for the trapezoid, the angle at A is 120, but it's not a vertex angle; but it is.

Let's think about the sum of interior angles.

For a quadrilateral, sum of interior angles is 360 degrees.

So, angle at A: 120

Angle at B: 3y+40

Angle at C: interior at C, which is 250 - 3x

Angle at D: x

Sum: 120 + (3y+40) + (250 - 3x) + x = 360

Simplify: 120 + 3y + 40 + 250 - 3x + x = 360

Combine like terms: 3y - 2x + 410 = 360

Then 3y - 2x = 360 - 410 = -50

So 3y - 2x = -50 (equation 1)

Now, if it's a trapezoid with AB || CD, then angle A + angle D = 180, so 120 + x = 180, x=60.

Then from equation 1: 3y - 2*60 = -50, 3y - 120 = -50, 3y = 70, y=70/3, same as before.

But if it's not a trapezoid with AB || CD, but with other sides parallel.

Suppose that AD || BC, but AD and BC are the legs, and if they are parallel, it would be a parallelogram, but sum of angles would be 360, but in parallelogram, opposite angles equal, etc.

Assume AD || BC.

Then, since AD || BC, and AB is a transversal, then angle at A and angle at B are consecutive interior angles, so they sum to 180 degrees.

Similarly, with DC as transversal, angle at D and angle at C sum to 180.

So, angle A + angle B = 180

120 + (3y+40) = 180

160 + 3y = 180

3y = 20

y = 20/3 not integer.

Then angle D + angle C = 180

x + (250 - 3x) = 180

250 - 2x = 180

-2x = -70

x = 35

Then sum of angles: 120 + (3*20/3 +40) = 120 + (20+40) = 120+60=180, good.

Angle D =35, angle C = 250 - 3*35 = 250-105=145, 35+145=180, good.

Sum: 120+60+35+145= let's see, 120+60=180, 35+145=180, total 360, good.

But y=20/3 not integer, and choices are integers.

20/3 is approximately 6.67, not in choices.

Suppose that AB || DC, but DC is the same as CD, so same as first case.

Or perhaps AC || BD, but that's the diagonals, not sides.

Another possibility: the parallel sides are the top and the bottom, but in the diagram, the bottom is not a single side; from A to D is bottom, but in the angle, at A and D are on the bottom.

Perhaps the parallel sides are the left side and the right side.

But left side is from A to B, right side from D to C.

If AB || DC, but DC is from D to C, which is the same as CD, but direction opposite, but parallel is the same.

If AB || DC, then since AB and DC are opposite sides, and if they are parallel, then for it to be a trapezoid, the other pair should not be parallel.

In this case, if AB || DC, then angle at A and angle at D are not necessarily supplementary; they are not on the same transversal.

If AB || DC, and AD is a transversal, then angle at A and angle at D are consecutive interior angles for transversal AD with parallel lines AB and DC.

Transversal AD intersects AB at A and DC at D.

Since AB || DC, then the consecutive interior angles are angle at A (between AB and AD) and angle at D (between DC and AD), and they are on the same side of the transversal AD, so they should be supplementary.

Yes, same as before: angle A + angle D = 180.

Similarly, if BC is transversal, angle B + angle C = 180.

So same as initial assumption.

But we have y not integer.

Perhaps the "right" in "right trapezoid" means that the non-parallel sides are perpendicular to the bases, but in this case, with angle at A 120, it's not perpendicular.

Or perhaps at D it is perpendicular.

Assume that at D, the angle is 90 degrees, so x=90.

Then from angle A + angle D = 180 for parallel bases, 120+90=210≠180, impossible.

So not.

Perhaps the bases are not horizontal; in the diagram, the 120 degrees is at the bottom left, so likely the base is horizontal.

Another idea: perhaps the exterior angle (3x-70) is for the angle at C, but for the trapezoid, when they say "angle at C", it might be the interior, but the label is outside, so it's exterior.

But in the sum, we have the interior angle.

Perhaps for the trapezoid, the vertex C has the exterior angle given, but the interior is what we need.

I think I have to consider that in a right trapezoid, there is a right angle, and perhaps it is at B or D.

Suppose that at D, angle is 90, so x=90.

Then, if we don't assume parallel sides yet, from sum of angles.

Interior angles: A: 120, D: 90, B: 3y+40, C: 250 - 3x = 250 - 270 = -20? Negative? Impossible.

250 - 3*90 = 250-270= -20, not possible.

If at B, angle is 90, so 3y+40=90, 3y=50, y=50/3.

Then interior at C: 250 - 3x

At D: x

Sum: 120 + 90 + (250 - 3x) + x = 360

120+90=210, 210 + 250 - 3x + x = 460 - 2x = 360

So 460 - 2x = 360, 2x = 100, x=50.

Then interior at C: 250 - 3*50 = 250-150=100.

Sum: 120 + 90 + 100 + 50 = 360, good.

But y=50/3 not integer.

If at C, interior angle is 90, so 250 - 3x = 90, 3x=160, x=160/3.

Then angle at D: x=160/3

Angle at B: 3y+40

Sum: 120 + (3y+40) + 90 + 160/3 = 360

250 + 3y + 160/3 = 360

3y = 360 - 250 - 160/3 = 110 - 160/3 = (330 - 160)/3 = 170/3

y = 170/9 not integer.

So no.

Perhaps the 120 degrees is not the interior angle at A, but the angle between the side and the base or something, but the diagram shows it at the vertex.

Another thought: in some contexts, "right trapezoid" means it has two right angles, and they are adjacent.

So assume that at A and at B, or at D and at C, etc.

Suppose at A and at D are right angles, but at A is 120, not 90.

Suppose at B and at C are right angles.

So angle at B: 3y+40 = 90, so 3y=50, y=50/3 not integer.

Angle at C: interior 250-3x=90, x=160/3 not integer.

Suppose at A and at B are right angles, but at A is 120, not 90.

Impossible.

At D and at C: angle at D x=90, angle at C 250-3x=90, then 250-3*90=250-270= -20 impossible.

At A and at C: at A 120, at C 90, then from sum: 120 + (3y+40) + 90 + x = 360

250 + 3y + x = 360

3y + x = 110

But we have two variables, need another equation from the parallel sides.

If we assume AB || CD, then angle A + angle D = 180, 120 + x = 180, x=60.

Then 3y + 60 = 110, 3y=50, y=50/3.

Same as before.

If we assume other parallel sides.

Suppose that the parallel sides are AD and BC.

But AD and BC are not opposite; in quadrilateral, opposite sides are AB and CD, or AD and BC.

If AD || BC, then it is a trapezoid with parallel sides AD and BC.

Then, with AD || BC, and AB as transversal, then angle at A (between AD and AB) and angle at B ( between BC and AB) are consecutive interior angles, so they sum to 180 degrees.

Similarly, with DC as transversal, angle at D and angle at C sum to 180.

So, angle at A + angle at B = 180

120 + (3y+40) = 180

160 + 3y = 180

3y = 20

y = 20/3 not integer.

Then angle at D + angle at C = 180

x + (250 - 3x) = 180

250 - 2x = 180

-2x = -70

x = 35

Then angles: A:120, B:3*(20/3)+40=20+40=60, C:250-3*35=250-105=145, D:35.

Sum: 120+60+145+35=360, good.

But y not integer.

Perhaps the "right" refers to the right angle at the intersection, but we need to find where the right angle is.

Maybe the 120 degrees is the only given, and we have to use that it's a right trapezoid, so one of the angles is 90.

But from the choices, y is 10,20,30,70, so angle B = 3y+40, if y=10, angle B=30+40=70; y=20, 60+40=100; y=30, 90+40=130; y=70, 210+40=250, which is impossible for an angle, less than 360 but in quadrilateral, angle can be up to 180 for convex, 250>180, so probably not, so y=70 is invalid for angle B.

Similarly, for angle at C, interior 250-3x, must be between 0 and 180, so 250-3x >0, 3x<250, x<83.33, and 250-3x <180, -3x< -70, x>70/3≈23.33.

Angle at D is x, between 0 and 180.

From sum, we have 3y - 2x = -50 from earlier equation.

Also, for it to be a trapezoid, one pair of sides parallel.

Suppose that it is a right trapezoid with right angle at D, so x=90.

Then from sum: 3y - 2*90 = -50, 3y - 180 = -50, 3y = 130, y=130/3 not integer.

If right angle at B, 3y+40=90, y=50/3 not integer.

If right angle at C, interior 250-3x=90, 3x=160, x=160/3, then from sum: 3y - 2*(160/3) = -50, 3y - 320/3 = -50, 3y = -50 + 320/3 = (-150 + 320)/3 = 170/3, y=170/9 not integer.

So no.

Perhaps the 120 degrees is the angle, but for the trapezoid, the "right" might mean something else, but I think not.

Another idea: perhaps "right trapezoid" means that it has a pair of right angles, but that doesn't make sense.

Or perhaps in some regions, it means something else.

Maybe the arrow indicates the direction of parallel, but in the diagram, the arrow on the left is horizontal, on the right is at an angle, but if they are parallel, they have the same slope, so the angle should be the same, but the angles at the vertices are different, so probably the arrows are on the parallel sides.

In the diagram, the bottom side and the top side might be the ones with the arrows, but the user didn't mention arrows on top and bottom; only mentioned the angles.

In the initial problem, for the first query, there was a diagram with heart and arrow, but for this one, it's a different diagram, and the user said "the following figure", but in text, only angles are described.

Perhaps in the diagram, the two sides with arrows are parallel, and from the angles, we can find which pair is parallel.

But in the text, it's not specified where the arrows are, only the angles are given.

The user said: "in the following figure", and then described the angles, but for the arrows, in the first part, there was a figure, but for this, it's a separate figure.

Looking back, the user said: "For the following figure," and then "Find the value of y", and then the choices, but no description of arrows in this context.

In the message, it's: "Find the value of the variable y in the right trapezoid. Choices: A:10 B:20 C:30 D:70" and then a image link, but no text description of the arrows.

In the initial message, for this query, it's: "Find the value of the variable y in the right trapezoid. Choices: A:10 B:20 C:30 D:70" and then an image, but since I can't see the image, I have to assume from the context.

Perhaps in the image, the arrows are shown, but in text, it's not described.

Maybe for this problem, the "right trapezoid" implies the parallel sides are perpendicular to the legs or something, but typically not.

Another thought: in a right trapezoid, there are two right angles, and they are on the same side.

So assume that at A and at D, there are right angles, but at A is 120, not 90.

Unless the 120 is at B or something.

Perhaps the 120 degrees is at the top or bottom, but not at the vertex for the angle.

I think I need to look for a different approach.

Let's assume that the trapezoid has a right angle at the bottom right, so x=90.

Then, the interior angle at C is 250 - 3*90 = 250-270= -20, impossible.

So not.

Perhaps the exterior angle is not at C, but at another vertex.

Or perhaps the (3x-70) is the interior angle at C.

Let me try that.

Suppose that (3x-70) is the interior angle at C.

Then, angles: A: 120, B: 3y+40, C: 3x-70, D: x.

Sum: 120 + (3y+40) + (3x-70) + x = 360

120 + 3y + 40 + 3x - 70 + x = 360

3y + 4x + 90 = 360 (since 120+40-70=90)

120+40=160, 160-70=90, yes.

So 3y + 4x + 90 = 360

3y + 4x = 270 (equation 2)

Now, for it to be a trapezoid.

Suppose AB || CD.

Then angle A + angle D = 180, 120 + x = 180, x=60.

Then from equation 2: 3y + 4*60 = 270, 3y + 240 = 270, 3y = 30, y=10.

y=10, which is choice A.

Then angle at C: 3*60 - 70 = 180 - 70 = 110.

Angle at B: 3*10 +40 = 30+40=70.

Sum: 120 + 70 + 110 + 60 = 360, good.

And with AB || CD, angle A + angle D = 120 + 60 = 180, good.

Angle B + angle C = 70 + 110 = 180, good.

Now, is it a right trapezoid? It has a right angle? At D, angle is 60, not 90; at B 70, not 90; at C 110, not 90; at A 120, not 90. But it is a trapezoid, and perhaps "right trapezoid" is a misnomer, or in some contexts, it just means trapezoid with a right angle, but here no right angle.

But y=10 is a choice, and it works mathematically.

Perhaps in this case, it is considered right because of the angles, but no.

Maybe the "right" refers to something else, but with y=10, it satisfies the trapezoid properties and sum.

Moreover, in the choices, 10 is an option.

Perhaps for this configuration, it is a right trapezoid if we consider the angles, but 60 and 90 are not present.

Unless at the other vertices, but no.

Perhaps with this, and the exterior angle was misinterpreted.

In the diagram, if (3x-70) is written at the top right inside, then it is interior.

But the user said "the following figure", and in the first query, there was an arrow, but for this, it might be different.

Since y=10 works, and it's a choice, probably that's the answer.

To confirm, if it is a right trapezoid, but with no right angles, but perhaps the problem allows it, or "right" is a name.

Perhaps in some definitions, but I think for the purpose, we can go with y=10.

So the answer should be 10.